urp:physgen

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1) objects in motion stay in motion, a body at rest stays at rest, until a force is applied ("law of inertia") 2) change in momentum of a body is equal in magnitude and direction to the force applied to it (force = mass * acceleration) 3) when two bodies interact, they apply forces that are equal to each other, and opposite in direction ("law of action and reaction")

Basic definitions:

- Force is in newtons or pounds. One newton = 1kg * m / s² (the force needed to accelerate 1kg at 1 m/s²)
- f = ma

- Momentum is p
- p = mv

- energy = work (joules) = force * distance
- J = F*d = applying 1 newton for 1 meter (units of kg * m²/s²)
- F = J/d

Fnet = Δp / Δt (since p = mv and Δv/Δtime = acceleration)

Change in potential energy is given by U=mgh

- potential energy:
- U = 1/2 kx² (spring), or
- P = mgh (at mass at some height, even on an inclined plane)

- kinetic energy: K = 1/2 mv²

**dimensional homogeneity** - units must be correct, parts added together, left side matches right side, etc.

Displacement is change in position.

s(t) = s0 + t*(v0+vt)/2 s = displacement from origin at time t vt = v0 + a*t if v0 = 0 then s(t) = s0 + t²*(a)/2 so in free-fall, from position 0, you have: s(t) = g * t²/2

**elastic**: Two objects bounce off each other. Kinetic energy, momentum conserved, no other energy created**inelastic**Two objects stick to each other. Momentum conserved, kinetic energy is not conserved (some energy converted to heat, sound, etc.)

conservation of momentum: p1i + p2i = p1f + p2f

for m1 having velocity u1 to the right, m2 initially at rest, ends with velocity v2. x dimension: m1u1 = m1u2cosθ1 + m2v2cosθ2 y dimension: 0 = m1u2sinθ1 - m2v2sinθ2

Glancing blow: If and only if both masses are equal (like billiards), then the angle between the resulting vectors is always 90 degrees.

normal force = force perpendicular to the plane normal force on a block resting on a slope, θ = degrees from horizontal: f = m*g*cos(θ) parallel force = force parallel to the inclined plane f = m*g*sin(θ) When parallel force > friction, it is unbalanced and objects will move down the plane Applied force - friction = net force

static friction - μS (mu static) = fS/N (fS = force where static friction is overcome N = normal force) must be overcome before the mass moves μS = fs/N = m*g*sin(θ) / m*g*cos(θ) = sin(θ)/cos(θ) = tan(θ) kinetic friction - normal moving friction only one type of friction applies at a time

Hooke's law for springs: F=-kx, k=spring constant, x = displacement

Fulcrum: t = r * f (torque = radius * force) just add the torques for multiple objects on one side of a fulcrum

Vx = Vo*cos(θ) Vy = Vo*sin(θ) - gt x = Vx*t y = Vy*t - g*t²/2

projectile follows the shape of a parabola

y = Ax² + Bx y = -gx²/(2(VoCos(θ))²) + xtan(θ) time of flight: t = 2Vosin(θ)/g max height: H = (Vosin(θ))²/2g distance: x = sin(2*θ)*Vo² / g

Vo = initial velocity Can use 2sin(θ)cos(θ) = sin(2θ) if filling in t with time of flight in the x = Vx*t formula

Vf² = Vi² + 2ad ?

pressure P = F/A (force/area) hydrostatic gauge pressure: P = pgh, p = density of fluid, g=gravity, h=height (depth) buoyant force Fb = Fup - Fdown

Fb = pgVf, where Vf = volume of displaced fluid, and density * volume = mass, so Fb = mf*g, where mf = mass of displaced fluid => buoyant force depends on mass of displaced fluid, not the mass of the object

gravitational constant between two bodies

F = G * m1 * m2 / r² and g = G * m1 / r² gE (gravity Earth) = 9.8 m/s²

no use of forces in the equations

typical equations: d = vo*t + 1/2*a*t² d = (vo + vf)/2 * t vf²= vo² + 2ad vf = v0 + at

coefficient of restitution = ratio of energy conserved after collision

e = (vel. after collision) / (vel. before collision) (for collision with immovable object) e = (Vfa * Vfb) / (Via * Vib) (for collision between objects a and b. f = final, i = initial velocity) e = 1 for perfectly elastic, 0 for perfectly inelastic

urp/physgen.1634519996.txt.gz · Last modified: 2021-10-18 by nerf_herder