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urp:poly [2021-12-19]
nerf_herder
urp:poly [2022-01-07] (current)
nerf_herder [Completing the square]
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-====Polynomials====+=====Polynomials=====
  
-=== Box method ===+==== Box method ===
 + {{ :​urp:​quad-box-method.png?​220|Image from basicmathematics.com}}
  
   - Make a 2x2 box (for a quadratic equation).   - Make a 2x2 box (for a quadratic equation).
   - Pull out the greatest common factor of the whole equation and keep it for later, if needed.   - Pull out the greatest common factor of the whole equation and keep it for later, if needed.
   - The x² coefficient goes in the upper left, the last term goes in the bottom right.   - The x² coefficient goes in the upper left, the last term goes in the bottom right.
-  - Multiply ​the terms and look for factors that will add up to the x coefficient.+  - Multiply ​those two terms (20x² in this example) ​and look for factors ​(1,20; 2,10; 4,5) that will add up to the x coefficient.
   - Pull out the greatest common factor for each row and column, and write them outside the box.   - Pull out the greatest common factor for each row and column, and write them outside the box.
   - The factors will be the parts outside the box: (2x+5)(x+2) in the example.   - The factors will be the parts outside the box: (2x+5)(x+2) in the example.
   - Multiply the GCF, if it was not 1.   - Multiply the GCF, if it was not 1.
-   + 
-(Image from basicmathematics.com)+
  
-=== Completing the square ===+==== Completing the square ​====
  
 start with quadratic equation: ax² + bx + c = 0 start with quadratic equation: ax² + bx + c = 0
-  ​go to: a(x+d)² + e = 0, + 
-    ​where d = b/(2a) and e = c - b²/(4a) +=== Method 1 === 
-  steps: ​divide by a to get x² by itself + 
-    x² + (b/a)x + (c/a) = 0 +  Rewrite as x² + (b/a)x = -c/a 
-  ​add & subtract ((b/a)/2)², now you have: +  That becomes (x + b/2a)² = -c/a + (b/2a)² 
-    x² + (b/a)x + ((b/a)/2)² + (c/a) ((b/a)/2)² = 0+  Call d = b/2a: (x + d)² = d² - c/a 
 +  Take square roots: x + d = ±√(d² - c/a), and simplify 
 +  (Solving for x gives two answers, call it u and v.  
 +   ​The quadratic equation can then be rewritten as: a(x+u)(x+v) = 0) 
 + 
 +=== Method 2 === 
 + 
 +Just compute the values: **equation of square: a(x+d)² + e = 0,** where d = b/(2a) and e = c - b²/(4a) 
 +    ​ 
 +  steps to get thereuse method 1 to get (x + d)² = d² - c/a 
 +  ​multiply both sides by a: a(x + d)² = ad² - c 
 +  call e = c - ad², then a(x + d)² + e = 0 
 +  ​
     (x + (b/a))² + c/a - ((b/a)/2)² = 0     (x + (b/a))² + c/a - ((b/a)/2)² = 0
     \==========/​     \==========/​
       quadratic ​  + remainder = 0       quadratic ​  + remainder = 0
-   -b/a is the vertex (x value) if graphing, y = remainder+       
 +-b/a is the vertex (x value) if graphing, y = remainder
  
 which leads to **quadratic formula**: x = (-b +- √(b²-4ac)) / 2a which leads to **quadratic formula**: x = (-b +- √(b²-4ac)) / 2a
  
-===Multiplicity of a polynomial===+==== Max and Min ==== 
 +Start with equation of square. 
 + 
 +  If a>0 then max = infinity, min is at x = -d 
 +  If a<0 then min = -infinity, max is at x = 0 
 + 
 + 
 +====Multiplicity of a polynomial====
  
 Multiplicity is the number of times a given factor appears in the factored form of the equation of a polynomial. Multiplicity is the number of times a given factor appears in the factored form of the equation of a polynomial.
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      This has 3 different polynomials for x, and will touch or cross the x axis 3 times      This has 3 different polynomials for x, and will touch or cross the x axis 3 times
  
-===Rational Roots===+====Rule of signs & Number of roots==== 
 +Roots of a polynomial are locations where y=0. Rule of signs can tell us how many roots exist, and how many have a positive or negative value of x. 
 + 
 +The highest power is the number of total roots. 
 +     
 +Count the number of times the sign of coefficient of terms changes sign (ignoring any zero coefficients) as you go down the list of coefficients.  
 + 
 +If there is no constant term (power of 0), pull out a factor of x, until there is a constant. For example: x³+2x²+5x gets changed to x(x²+2x+5),​ then use x²+2x+5 in the steps below. (Total number of roots is from original equation: 3 in this case.) 
 + 
 +   ​Example:​ 
 +     ​-3x⁴ + 4x² + x − 2  
 +     
 +    Positive Roots: This has two changes in sign, so a maximum of two positive roots 
 +    Negative Roots: Substitute -x => only odd powers will change sign. Count the changes in sign again. 
 +    In this example, only the x changes: -3(-x)⁴ + 4(-x)² + -x − 2 = -3x⁴ + 4x² -x − 2 
 +         still two changes => two negative roots (or 0 if there'​s complex roots) 
 +    The number of positive or negative roots is reduced by 2 for each pair of complex roots, if they exist. 
 +    That means, in this case, there could be: 
 +      * 4 roots: 2 positive roots, 2 negative roots 
 +      * 4 roots: 0 positive roots, 2 negative roots, complex pair 
 +      * 4 roots: 2 positive roots, 0 negative roots, complex pair 
 +      * 4 roots: 0 positive roots, 0 negative roots, 2 complex pairs     
 + 
 +====Rational Roots====
 What are all the possible rational roots of the following function: 6x⁴−x³−4x²−x−2 What are all the possible rational roots of the following function: 6x⁴−x³−4x²−x−2
  
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 When the leading coefficient is 1, the possible rational zeros are the factors of the constant term. When the leading coefficient is 1, the possible rational zeros are the factors of the constant term.
  
 +------------
 +
 +Back to the [[00_start|Start]] page or [[math]] page.
  
urp/poly.1639944277.txt.gz · Last modified: 2021-12-19 by nerf_herder